Answer by Especially Lime for Definition of mean of a random variable in...
Certainly $\mu_X=\sum_xxf(x,y)$ cannot be right, because the RHS is a function of $y$.As you say, it should be $\mu_X=\sum_x\sum_yxf(x,y)$. That is also clearly what the author meant, since that is...
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Definition of mean of a random variable in joint probability distribution?
I am reading the "Probability & Statistics for Engineers & Scientists" 9th edition and encounter a proof of theorem 4.4 where it said:$$\mu_{X}=\sum_{x}xf(x,y),\ \ \mu_{Y}=\sum_{y}yf(x,y)$$...
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